Lua常用时间函数

时间函数

-- 获取当前的格林尼治时间print(os.time())

-- 获取当前时间的字符串表⽰，形如：11/28/08 10:28:37print(os.date())

-- 获取当前⽇期的字符串表⽰，形如：11/28/08print(os.date(\"%x\", os.time()))

-- 获取当前时间的字符串表⽰，形如：10:28:37print(os.date(\"%X\", os.time()))

-- 获取当前时间的字符串表⽰，形如：10/10/13 10:28:37print(os.date(\"%c\", os.time()))

-- 获取当前时间的字符串表⽰，形如：2013-10-10 10:28:37print(os.date(\"%Y-%m-%d %H:%M:%S\", os.time()))

--函数os.clock返回执⾏该程序CPU花去的时钟秒数local x1 = os.clock()local s = 0

for i = 1, 10000000 dos = s + iend

local x2 = os.clock()

print(string.format(\"elapsed time: %.2f\\n\", x2 - x1))

local T2009_StartTime = { year=2013, month=2, day=9, hour=0, min=0, sec=0 }local T2009_EndTime = { year=2013, month=2, day=17, hour=23, min=59, sec=59 }

T2009_AvtivityTime = { startTime = os.time(T2009_StartTime), endTime = os.time(T2009_EndTime) }

print('加载礼包活动成功，活动时间：' .. os.date('%c', T2009_AvtivityTime.startTime) ..'~' .. os.date('%c', T2009_AvtivityTime.endTime))

temp = os.date(\"*t\", os.time())print(temp)--[[则会产⽣表

{year = 1998, month = 9, day = 16, yday = 259, wday = 4, hour = 23, min = 48, sec = 10, isdst = false}--]]

字符串与时间戳转化

时间戳转成格式化字符串

local timestamp = 1561636137;

local strDate = os.date(\"%Y/%m/%d %H:%M:%S\", timestamp)print(\"strDate = \", strDate);

字符串转化成时间戳

分离

local strDate = \"2019/06/27 19:48:57\"

local _, _, y, m, d, hour, min, sec = string.find(strDate, \"(%d+)/(%d+)/(%d+)%s*(%d+):(%d+):(%d+)\"); --分离字符串 前两个不知道是什么？

print(y, m, d, hour, min, sec);

转化

--转化为时间戳

local timestamp = os.time({year=y, month = m, day = d, hour = hour, min = min, sec = sec});print(\"timestamp = \", timestamp);